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Date: 06 Jul 2006 07:45:10
From:
Subject: Priming rate
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This ought to be a simple one for most of you out there. I on the other
hand have drawn a blank. I recently brewed a batch with way more trub
than I had planned for so as a result I ended up with seven gallons of
beer. Now most brew text give the priming rate for five gallons useing
either DME or corn sugar. Yet when you have a odd amount like seven
gallons a algebraic equation could solve for it but it's still out of
reach for me. So gang, how much corn sugar do I need to prime seven
gallons? Thanks for your help.
Steve
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Date: 06 Jul 2006 15:29:07
From: John 'Shaggy' Kolesar
Subject: Re: Priming rate
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On 6 Jul 2006 07:45:10 -0700, <smhoneydo@aol.com > wrote:
> This ought to be a simple one for most of you out there. I on the other
> hand have drawn a blank. I recently brewed a batch with way more trub
> than I had planned for so as a result I ended up with seven gallons of
> beer. Now most brew text give the priming rate for five gallons useing
> either DME or corn sugar. Yet when you have a odd amount like seven
> gallons a algebraic equation could solve for it but it's still out of
> reach for me. So gang, how much corn sugar do I need to prime seven
> gallons? Thanks for your help.
X / 5 = Y / 7
X is the original amount called for, lets call it 4 oz by weight just to
pick a number (4 oz ~= 3/4 cup). If you normally use something else for 5
gallon batches then substitute that number. Y is the amount you would use
for a 7 gallon batch.
4 / 5 = .8
.8 = 5.6 / 7
Another way to think about it is that if you use 4 oz per 5 gallons, then
4 / 5 = .8 means that you are using .8 oz of priming sugar per gallon of
beer. From that point, you can just multiply .8 by your batch size to
get the priming amount for any size you want. In this case,
.8 * 7 = 5.6 oz
John.
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Date: 06 Jul 2006 11:32:52
From:
Subject: Re: Priming rate
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John 'Shaggy' Kolesar wrote:
> On 6 Jul 2006 07:45:10 -0700, <smhoneydo@aol.com> wrote:
> > This ought to be a simple one for most of you out there. I on the other
> > hand have drawn a blank. I recently brewed a batch with way more trub
> > than I had planned for so as a result I ended up with seven gallons of
> > beer. Now most brew text give the priming rate for five gallons useing
> > either DME or corn sugar. Yet when you have a odd amount like seven
> > gallons a algebraic equation could solve for it but it's still out of
> > reach for me. So gang, how much corn sugar do I need to prime seven
> > gallons? Thanks for your help.
>
> X / 5 = Y / 7
>
> X is the original amount called for, lets call it 4 oz by weight just to
> pick a number (4 oz ~= 3/4 cup). If you normally use something else for 5
> gallon batches then substitute that number. Y is the amount you would use
> for a 7 gallon batch.
>
> 4 / 5 = .8
>
> .8 = 5.6 / 7
>
>
> Another way to think about it is that if you use 4 oz per 5 gallons, then
> 4 / 5 = .8 means that you are using .8 oz of priming sugar per gallon of
> beer. From that point, you can just multiply .8 by your batch size to
> get the priming amount for any size you want. In this case,
>
> .8 * 7 = 5.6 oz
>
>
> John.
Thanks John, that works for me!
Steve
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